Each diagonal of a rhombus would never bisect a pair of opposite angles, but the diagonals are perpendicular to each other
no
Rhombus.....
That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
The length of the other diagonal works out as 12cm
The diagonals of a rhombus are perpendicular. A rhombus is a special kind of parallelogram. It has the characteristics of a parallelogram (both pairs of opposite sides parallel, opposite sides are congruent, opposite angles are congruent, diagonals bisect each other.) It also has special characteristics. It has four congruent sides. So it looks like a lopsided or squished square. Its diagonals are perpendicular. Another property: each diagonal bisects two angles of the rhombus.
Yes. In a rhombus (and in a square), the opposite angles that each diagonal connects are bisected by the diagonal.
no
Not always, sometimes they are perpendicular.
The length of the rhombus is equal to the length of the diagonal formed by the bisector of the 2 opposite acute angles.
The diagonals of a rhombus are perpendicular and intersect each other at right angles which is 90 degrees
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
A square, a rhombus or s kite would fit the given description
Yes.
The main difference between a square and a rhombus is that a square has all its angles equal to 90 degrees and a rhombus does not. A square has 4 lines of symmetry while rhombus only has 2. The diagonal lengths of a square are of the same measure. Rhombus diagonal lengths are of different measures. They are both a quadrilateral, all sides are equal in length, and opposite sides are parallel to each other.
Yes.Yes.Yes.Yes.
Rhombus Area = side x height = 6 cm x 4 cm = 24 cm2In the right triangle formed by the side and the height of the rhombus, we have:sin (angle opposite to the height) = height/side = 4 cm/6cm = 2/3, so thatthe angle measure = sin-1 (2/3) ≈ 41.8⁰.In the triangle formed by two adjacent sides and the required diagonal, which is opposite to the angle of 41.8⁰ of the rhombus, we have: (use the Law of Cosines)diagonal length = √[62 + 62 -2(6)(6)cos 41.8⁰] ≈ 4.3Thus, the length of the other diagonal of the rhombus is about 4.3 cm long.
Area=ba where b=base (any side), and a=altitude, the perpendicular length from the base to the opposite sideORArea= (d1*d2)/2 where d1 is the diagonal and d2 is the other diagonal