Certainly! Let's go through the implementation step by step:
We start by declaring three main data structures:
stack
: A stack data structure to store the elements in the order they are pushed.
Frequencyy Map`: A map to track the frequency of each element in the stack.
frequency Stack Map
: A map that maps frequencies to stacks. This will help us track the elements with the same frequency.
The constructor initializes the data structures and sets the initial maximum frequency to 0.
The `push` method takes an integer `x` as input and performs the following steps:
Increments the frequency of element `x` in the frequency Map
.
Updates the maximum frequency if necessary.
If a stack for the current frequency does not exist in frequency Stack Map
, a new stack is created.
Pushes element `x` into the stack corresponding to its frequency in frequency Stack Map
.
Pushes element `x` onto the main stack
.
The `pop` method removes and returns the most frequent element from the stack. If there are multiple elements with the same highest frequency, it returns the one that was pushed most recently. The steps involved are:
Retrieves the top element from the stack with the maximum frequency in frequency Stack Map
.
Decrements the frequency of the element in frequency Map
.
If the stack for the maximum frequency becomes empty, we decrement the maximum frequency.
Removes the element `x` from the main `stack` using the `remove Element` method.
Returns the popped element x
.
The `get Frequency` method takes an integer `x` as input and returns its frequency from the frequency Map
.
The implementation keeps track of the frequencies of elements in `frequency Map` and uses `frequency Stack Map` to map frequencies to stacks. This allows us to efficiently retrieve the most frequent element and handle multiple elements with the same highest frequency.
I hope this explanation helps! Let me know if you have any further questions.
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