1/16
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
A number cube has six faces, so the probability of any one of them showing on a fair throw is 1 in 6, or about 0.1667.
in the equation system f/d = p where f is the number of sides of the rolled polyhedron which contain a number of spots that can be represented by a positive integer not divisible by 2 and d represents the total number of faces of the polyhedron which can, in the rest position, face upward, the variable p represents the probability of rolling an odd number. from this it can also be derived that the probability p of rolling an even number can be represented by (d-f)/d.
There could be many questions: What is the probability of rolling an even number. What is the probability of rolling an odd number. What is the probability of rolling a number less than 4. What is the probability of rolling a number more than 3. What is the probability of rolling 1,4, or 6. Basically it could be any question about the probability of rolling half of the faces.
On a single roll, the probability is 1/2.
The probability is 0.277... (repeating).
there are 6 faces of the dice so the answer is 1/6
A fair cube is a die which, when rolled, has a probability of 1/6 of coming to a stop with each of the faces uppermost.
Probability is desired options over total options. There are 6 faces on a standard dice, so NOT rolling a 5 is 5/6.
When a tetrahedral die is rolled, it will rest with three faces upwards. If the die is numberd from 1 to 4. therefore the sum of the upward facing numbers on 1 die is at least 6 and so for two dice, the minimum is 12. That being the case, the probability is 0.
Prob = 4/36 = 1/9
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
A number cube has six faces, so the probability of any one of them showing on a fair throw is 1 in 6, or about 0.1667.
There are six faces, and only three faces with a number higher than a four. So it is 3 chances in 6.
in the equation system f/d = p where f is the number of sides of the rolled polyhedron which contain a number of spots that can be represented by a positive integer not divisible by 2 and d represents the total number of faces of the polyhedron which can, in the rest position, face upward, the variable p represents the probability of rolling an odd number. from this it can also be derived that the probability p of rolling an even number can be represented by (d-f)/d.
There could be many questions: What is the probability of rolling an even number. What is the probability of rolling an odd number. What is the probability of rolling a number less than 4. What is the probability of rolling a number more than 3. What is the probability of rolling 1,4, or 6. Basically it could be any question about the probability of rolling half of the faces.