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How do you find the perimeter of an isosceles trapezoid when one of its parallel sides is 6cm greater than its other parallel side and has a height of 4cm with an area of 34cm?
Wiki User
∙ 12y ago
First find the lengths of the parallel sides and let the parallel sides be x+6 and x:
1/2*(x+6+x)*4 = 34 sq cm
Multiply both sides by 2 and then divide both sides by 4:
2x+6 = 17
Subtract 6 from both sides and then divide both sides by 2 to to find the value of x:
x = 5.5
Therefore the parallel sides are: 5.5cm and 11.5cm
Each side of the trapezoid will have a right angle triangle with a base of 3 and a height of 4 and by usiing Pythagoras' theorem each hypotenuse works out as 5cm
So the perimeter is: 5.5+11.5+5+5 = 27cm
Wiki User
∙ 12y ago
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What is the perimeter of an isosceles trapezoid when one of its parallel lines is greater by 10.5 cm than its other parallel side and has height of 7 cm with an area of 106.75 square cm?
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Yes.
Is a greater perimeter going to have a greater area can you show a picture?
yes it will have a greater area
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They can vary in size. In its most general form, a trapezoid (or trapezium, outside of North America) is a four-sided figure with exactly one pair of parallel sides. The two parallel sides do not have to be the same length; therefore a trapezoid will have either:Two acute angles (less than 90º) and two obtuse angles (greater than 90º) ORTwo right angles, one acute angle, and one obtuse angle.Case (2) is a special type of Case (1).Regardless of its configuration, the interior angles of a trapezoid always add up to 360 degrees
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It depends on the sizes of the two shapes.
Can a rectangle have a greater perimeter than another one but have a greater area too?
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One or two.
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No it depends on the size of the polygon
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