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What is secant pi over 6?

Updated: 12/15/2022
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6y ago

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It is 2*sqrt(3)/3.

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Q: What is secant pi over 6?
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What is the period of secant?

2*Pi


What is the period of co-secant?

2*pi radians.


When is secant not defined?

The secant of an angle is the reciprocal of the cosine of the angle. So the secant is not defined whenever the cosine is zero That is, whenever the angle is a multiple of 180 degrees (or pi radians).


In trigonometry what are three values that are not defined?

Cosecant of k*pi radians Secant of 0.5*(2k+1)*pi radiansCotangent of k*pi radianswhere k is an integer.


Why is the period of secant 2 pi?

It is the same period as cosine function which is 2 pi because sec x = 1/cos x


What are the values of theta of which secant theta is undefined?

Since secant theta is the same as 1 / cosine theta, the answer is any values for which cosine theta is zero, for example, pi/2.


What is the trigonometric function sec?

The function sec(x) is the secant function. It is related to the other functions by the expression 1/cos(x). It is not the inverse cosine or arccosine, it is one over the cosine function. Ex. cos(pi/4)= sqrt(2)/2 therefore secant is sec(pi/4)= 1/sqrt(2)/2 or 2/sqrt(2).


What is an secant in math?

Secant is a trignometric function. In a right triangle, the secant of an angle is the hypotenuse over the adjacent side. It is also the inverse of cosine. For example secant(x) = 1/cos(x)


Why dont you have buttons for cotangent secant cosecant?

You don't have buttons for cotangent, secant, and cosecant because you don't need them. Just invert. Cotangent is 1 over tangent, secant is 1 over sine, and cosecant is 1 over cosine.


What is 6 over 7 minus 1 over 3?

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What is the exact value of the expression cos 7pi over 12 cos pi over 6 -sin 7pi over 12 sin pi over 6?

cos(a)cos(b)-sin(a)sin(b)=cos(a+b) a=7pi/12 and b=pi/6 a+b = 7pi/12 + pi/6 = 7pi/12 + 2pi/12 = 9pi/12 We want to find cos(9pi/12) cos(9pi/12) = cos(3pi/4) cos(3pi/4)= cos(pi-pi/4) cos(pi)cos(pi/4)-sin(pi)sin(pi/4) cos(pi)=-1 sin(pi)=0 cos(pi/4) = √2/2 sin(pi/4) =√2/2 cos(pi)cos(pi/4)-sin(pi)sin(pi/4) = - cos(pi/4) = -√2/2


What is the secant of 3pi over 4?

Secant(3pi/4) = 1/cos(3pi/4) = 1/[-1/sqrt(2)] = -sqrt(2)