I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=
Area of a equilateral triangle="root over of 3" /4 * "a square"
Now I use this formula,
where "a" is 10. So the answers come=43.3,which is 44.
So the Correct answer is=44 inches.
* * * * *
Mostly correct, but:
An equilateral triangle with sides of 10 inches cannot have a height of 7 inches.
An equilateral triangle with sides of 10 inches has a height of 8.66 inches
or
an equilateral triangle with a height of 7 inches has sides of 8.08 inches.
Decide which triangle you want and then resubmit your question.
Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
27.713 square inches.
No. a equilateral triangle does not have perpendicular sides.
All triangles have exactly three sides. This is true whether the triangle is equilateral or not. If the triangle is equilateral, then the three sides will all be equal in length.All triangles have three sides.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.
The triangle with sides measuring 9 inches, 9 inches, and 9 inches is an equilateral triangle.
There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
18 inches and it is an equilateral triangle
An equilateral triangle...
Height of an equilateral triangle = √3 / 2 x side = (√3 / 2 ) x 3 = 2.598 cm.
Height of an equilateral triangle = √3/2 x side = √3/2 x 20 = 10√3 ≈ 17.32
27.713 square inches.
If it's an equilateral triangle with 10 inch sides its height is about 8.66 inches and not 7 inches. So: area = 0.5*10*8.66 = 43.3 square inches Or: area = 0.5*10*10*sin(60) = 43.3 square inches to 1 decimal place