Correct and easier way: Kinetic friction is just a part of magnitude of forces affecting an object, so it can be multiplied by g(9.81) to get the total acceleration essentially. Coefficient(.3)=F(friction)/F(normal) So multiply .3 by g(9.81) to get 2.943 -2.943 is the acceleration of the object, as it's slowing down) So then, simply multiply by time (1.3) to get a Vi of 3.8259 Ffriction = -0.3 * m * g = m * a a = -0.3 * g So if we integrate over time: v(t) = -0.3 * g * t + v(0) We know that v(t=1.3) = 0. So we can place it in the equation. v(t=1.3) = 0 = -0.3 * g * 1.3 + v(0) v(t=0) = 0.3*1.3*g = 0.39 * g = 0.507 meters per second
This is what my piano teacher taught me :D This means the note is going up: ^ This means the note is going down: v Sharp : # Flat : b B ^ E ^ G v F# v E ^ B v A v F# E ^ G v F# v D ^ F v B B ^ E ^ G v F# v E ^ B ^ D v C# v C A ^ C v B v Bb v B ^ G v E G ^ B v G ^ B G ^ C v B v Bb v F# ^ G ^ B v Bb v C v B ^ B G ^ B v G ^ B G ^ D v C# v C v A ^ C v B v Bb v B ^ G v E Hope this has helped :D
G. V. G. Raju was born in 1962.
D=E/((1+v)(1-2v))*[1-v v v 0 0 0; v 1-v v 0 0 0; v v 1-v 0 0 0; 0 0 0 0.5(1-2v) 0 0; 0 0 0 0 0.5(1-2v); 0 0 0 0 0 0.5(1-2v)]
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G. V. Iyer was born in 1917.
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