p --> q and q --> p are not equivalent p --> q and q --> (not)p are equivalent The truth table shows this. pq p --> q q -->(not)p f f t t f t t t t f f f t t t t
P Q (/P or /Q) T T F T F T F T T F F T
Suppose you have a variable which grows at r% per period [year] and you want to find out how many periods, t, it will take before it grows, from a starting value of P to reach the value Q.The approximate method used by younger pupils is trial and error. This is because the y do not have the necessary mathematical knowledge.After t periods, the variable in question will have increased from P to Q whereQ = P*(1+r/100)tthen Q/P = (1+r/100)ttaking logarithms, log(Q/P) = log[(1+r/100)t] = t*log(1+r/100)and so finally, t = log(Q/P) / log(1+r/100).
p > q~qTherefore, ~p| p | q | p > q | ~q | ~p || t | t | t | f | f || t | f | t | t | f || f | t | t | f | t || f | f | t | t | t |
P | T T F F Q | T F T F Q' | F T F T P + Q' | F T F F The layout is the best I could do with this software. Hope it is OK.
A. T. Q. Stewart was born in 1929.
A. T. Q. Stewart died in 2010.
There are 100 questions in this quiz.
The duration of Q. T. Hush is -300.0 seconds.
The starting value is Q(0) = (1/3)^(0/25) = (1/3)^0 = 1 Growth rate (per period, t) = 100*{Q(1)/Q(0)-1} = 100*{(1/3)^(1/25)/1 - 1} = 100*{0.9570 - 1} = -4.30 % approx.
t wer ewq qet rew er t e q q / r yi uyt wt ree rt e q q / t e r w e q $ / t e r w eti (
Q. T. Hush was created on 1960-09-24.