#include#includevoid main(){int a=0,b=1,c,i=2,n;clrscr();printf("enter no");scanf("%d",&n);if(n==0)printf("%d\n",a);elseprintf("%d\n %d\n",a,b);while(i
BJT is nothing but the addition of two PN junction diodes. There are two types of BJT= P-N-P or N-P-N P-N N-P + or + N-P = P-N-P P-N =N-P-N SCR is a thyristor which is made adding two BJTs. Of course they are made of sillicon. Exempli gratia: P-N-P + + N-P-N = P-N-P-N comparison between scr bjt and mosfet Check the related link for further information.
// Use the & operator (Sometimes called the "address of" operator int variable = 7; printf("Address of variable = %d\n", &variable); printf("Value of variable = %d\n", variable);
//to display 'n' natural numbers using for loop......(in C)..... #include<stdio.h> main() { int n,i; printf("\n Enter the range......Please...\t"); scanf("%d",&n); printf("\n Range of Natural Numbers.....\t"); for(i=1;i<=n;i++) { printf("\t%d",i); } }
It is basically composed of p or p+ or n or n+ impurities.
c o n p u e
N-14 has more protons. It contains one more proton than C.
Dereferencing a pointer returns the value stored at the memory location being pointed at, according to the type of pointer.Consider the following code. c is a char type and p is a pointer to a char type. c is assigned the value 'X' (88 decimal, 0x58 hexadecimal) while p is assigned the address of c, using the addressof operator &.The remainder of the code prints the address and value of both c and p, and also the dereferenced value of p. Note that you cannot dereference c since it is an alias for a reference, not a pointer to a reference.Note how the value of p is the memory address of c, while the dereferenced value of p is the value of p. note also that pointers are variables like any other, and therefore occupy memory of their own, as shown by the address of p.#include using namespace std;int main(){char c = 'X';char * p = &c;printf( "Address and value of c:\n" );printf( "&c = 0x%.8x\n", &c );printf( " c = 0x%.2x (%u) '%c'\n", c, c, c );cout
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what a what p what a what a what a what c what a what m what a what a what a what n
void main() { int n=0,i,*p; clrscr(); printf("enter the value of n"); scanf("%d",&n); p=&n; for(i=0;i<=n;i++) { *p=*p+i; } printf("value of the sum is %d",*p); getch(); }
what is the full meaning of N.N.P.C.?
pronunciation
A-C-C-E-P-T-I-N-G is how accepting is spelled.
#include<stdio.h> #include<conio.h> main() { int a[10][10],b[10][10],c[10][10],m,n,i,j,p,q,op; printf("enter the order of matrix a:n"); scanf("%d",&m,&n); printf("enter the %d elements of a\n",m*); for(i=0;i<m;i++) for(j=0;j<n;j++) scanf("%d",&a[i][j]); printf("enter the order of matrix b:n"); scanf("%d",&p,&q); printf("enter the %d elements of b\n",p*q); for(i=0;i<p;i++) for(j=0;j<q;j++) scanf("%d",&b[i][j]); printf("enter the option\n"); scanf("%d",&option); switch(op) { case '+' : if(m==p&&n==q) printf("the resultant matrix c is:\n"); for(i=0;i<m;i++) for(j=0;j<n;j++) c[i][j]=a[i][j]+b[i][j]; printf("%d",c[i][j]); printf("\n"); break; case '/' : if(n==p) { for(i=0;i<m;;i++); {for(j=0;j<q;j++) {printf("%d",c[i][j]); } } c[i][j]=0; for(p=0;p<n;p++) c[i][j]=c[i][j]+a[i][p]*b[p][j]: } printf("resultant matrix is:\n"); for(i=0;i<m;;i++); {for(j=0;j<q;j++) {printf("%d\t",c[i][j]); } } printf("\n"); getch(); }
If c = 1/8 πn2p, then p = 8c / (πn2)
U u t e c p n