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1 What average force is needed to accelerate a 7.0-gram pellet from rest to 175 ms over a distance of 0.700 m along the barrel of a rifle?
Wiki User
∙ 14y ago
Assuming all your numbers have metric measurements ... 125 m/s , 0.800 m...
s = vot + 0.5 at2 ..... a = (vf - vo) /t
0.8 = 0 + .5 at2 ..... at = 125 - 0
1.6 = at2 .... t = 125 / a
1.6 = a(125/a)2
1.6 = (15625/a)
a = 15625/1.6 = 9765.625 m/s2
F = ma = 0.009 kg x 9765.625 = 87.890625 newtons
Wiki User
∙ 11y ago
The average force needed to accelerate the pellet can be calculated using the equation ( F = m \cdot a ), where ( F ) is the force, ( m ) is the mass of the pellet, and ( a ) is the acceleration. First, convert the mass to kilograms (7.0 grams = 0.007 kg), and then calculate the acceleration using the formula ( a = \frac{{v^2 - u^2}}{2d} ), where ( v ) is the final velocity, ( u ) is the initial velocity (0 m/s in this case), and ( d ) is the distance. Finally, plug in the values to find the average force required.
Wiki User
∙ 14y agoThere are many different ways to do this problem, but here is how I did it:
Set up the equation v^2-v initial^2=2adeltax and solve for a
1.75^2=2a(.07KG*)
*remember to convert 7 g to kg
then you take the acceleration, 2.1875 and plug it into the equation:
F=ma
F=(.007)(2.188)
F=.015N
Wiki User
∙ 11y ago16.4
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