3.14 value of pi to the second decimal point
This depends on your definition. One could say that circles ({p in R^n : d(p,m) = r}) are concave, while (open) disks ({p in R^n : d(p,m) < r}) are convex.
if O is the center of the circle and P is on its circumference, then OP is a radius
1/3rd is 33.3333 recurring %
a, b. d. e, g, o, p and q.a, b. d. e, g, o, p and q.a, b. d. e, g, o, p and q.a, b. d. e, g, o, p and q.
The length of BAC in a circle P where BC is 24ft is 3p and not 6p 12p or 24p.
Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle." by arup nandy
Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle."
Pitch Circle Diameter (gears or chainwheels)
This depends on your definition. One could say that circles ({p in R^n : d(p,m) = r}) are concave, while (open) disks ({p in R^n : d(p,m) < r}) are convex.
it's a puzzle! it goes o... f... p... of w... on c.s, and the ... are the rest of the word. this person wants to know the answer, but so do i. i have homework on it, so if you want to add please do! hope this "hint" helped!! :) :0 :P :D <3 8o ;D
If you are referring to the crossword puzzle hint, try epi.
I assume you want to find the area of a circle? Let p = pi = 3.14, r = radius, d = diameter, a = area and c = circumference. a = pr2 a = pd2/4, where r = d/2 a = c2/4p, where d = c/p
I mean this in the nicest way possible: You're nuts!!!!! :P :D :P :D :P :D :P :D :P :D :P :D :P :D
The length (circumference) of the curved part of a semi-circle is pi times the radius (pi*R). If the diameter is given, then the semi-circle length is 1/2 (pi * x D) because the radius is 1/2 of the diameter.(There are 2pi radians in a full circle.)A closed shape formed from a semi-circle has a perimeter P = D + (pi * D / 2)(diameter plus the curved part)
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opesoncmrsi is a good hint
Diameter d = 2 × rDiameter d = C / pDiameter d = square root (4 A / pi)Circumference C = 2 p x r = p × d = square root (4 pi × A)Area A = pi × (d × d / 4) = C2 / (4 × pi)Radius rScroll down to related links and look at "Circle - Math Forum".