A 0.400-kg object undergoing SHM has ax -2.70 ms2 when x 0.300 In What is the time for one osci1lation?

Answer 1

T = t, because T = seconds/cycle.. It says there time for once oscillation.

So, first is to find the w.

a max = -w^2(x)

squareroot of [(-2.70m/s^2)/-x] = w

w = 3 rad/s

w = 2pi(f)

w/2pi = f

3rad/s / 2pi = f

f= 0.48

T = 1/f

T = 2.08 seconds

Answer 2

The time period for one oscillation in simple harmonic motion can be found using the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. Given that a = -2.70 m/s^2, we can calculate the spring constant k = -ma = -0.400 kg * -2.70 m/s^2 = 1.08 N/m. Plugging this value into the formula, we get T = 2π√(0.400 kg / 1.08 N/m) ≈ 1.84 seconds for one oscillation.