Its pythagoras: 102 - 52 = vertical height2. So 100-25 = vertical height2. Then the square root of 75 must = vertical height. Which makes the top of the ladder 8.66 feet (8ft 8 inches) from the ground.
5 meters
x^2=(x-4)^2+y^2 height up the wall = y = (x^2-(x-4)^2)^1/2 so if the length of the ladder is 10 feet Y= (100-36)^1/2 = 8
112
No. if the floor is smooth you must have friction between the ladder and the floor, or the ladder would just slide away. Technically you could do without friction between wall and ladder, but even that can be helpful in preventing the ladder from going sideways.
19
5 meters
5 meters
25.99 ft
A. 11 feet B. 13 C. 12 D. 14.
It is: 24 feet by using Pythagoras' theorem
9.2
93
12
12 feet.
56
x^2=(x-4)^2+y^2 height up the wall = y = (x^2-(x-4)^2)^1/2 so if the length of the ladder is 10 feet Y= (100-36)^1/2 = 8