9200 volts
my 1000 uF capacitor only holds 10 volts
A: SURE capacitors in parallel will share the charge. But don't expect a .0001 mfd capacitor to charge a 1000 mfd capacitor. It just does not have the power stored to effectively charge the 1000 mfd. EXAMPLE 1litter of water cannot fill up a 5 litter container
1000 microfarads is its rated capacitance, while 35 volts is its rated voltage.
A capacitor meter measures the value of a capacitor in pf (picofarads), nf (nanofarads), uf (microfarads) or even farads. There are a million uf in a farad, 1000 nf in a uf, and 1000 pf in a nf. A farad is a very large amount of capacity. The capacity tells you how much energy the capacitor can store from a voltage source.
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
The main difference between a 1n4004 and a 1n4007 are in the maximum RMS voltage, the maximum DC blocking voltage and the maximum repetitive peak reverse voltage. These are 280 and 700, 400 and 1000, and 400 and 1000 volts respectively.
A: SURE capacitors in parallel will share the charge. But don't expect a .0001 mfd capacitor to charge a 1000 mfd capacitor. It just does not have the power stored to effectively charge the 1000 mfd. EXAMPLE 1litter of water cannot fill up a 5 litter container
1000 Amps
1000 microfarads is its rated capacitance, while 35 volts is its rated voltage.
A capacitor meter measures the value of a capacitor in pf (picofarads), nf (nanofarads), uf (microfarads) or even farads. There are a million uf in a farad, 1000 nf in a uf, and 1000 pf in a nf. A farad is a very large amount of capacity. The capacity tells you how much energy the capacitor can store from a voltage source.
It will take slightly less than one second (0.92 seconds) to charge a 1000uF capacitor to 12 volts through a 1000 ohm resistor if your power source is 20 volts.The time constant of a 1000uF capacitor in series with a 1000 Ohm resistor is 1 second. (1x10-3 Farads times 1x10+3 Ohms = 1 second) It takes 1 time constant to reach 63% of a step change, 2 time constants to reach 86% of step change, and so forth using the equation VT = V0 (1 - e (-T/RC)). See notes below12 is 60% of 20, so it will take about 0.92 seconds for the capacitor to reach 12 volts. In two seconds the capacitor will reach about 17 volts. In five seconds, five time constants, the capacitor will be considered to be fully charged, 99.3%, to 20 volts.Notes:VT is voltage after a given number of seconds. V0 is the total initial voltage, in this case, 20 volts. -T/RC is the negative number of time constants for the exponential equation e-TC, which a charging capacitor exhibits. (More specifically, e-TC is the proportion of voltage across the resistor, while 1 - e-TC is the proportion of voltage across the capacitor.)This equation is based on the fundamental equation of a capacitor...dv/dt = i/c... which states that the slope of the voltage is proportional to current and inversely proportional to capacitance. Plug this into an initial state differential equation, for the case of charging an initially discharged capacitor through a resistor, and you getVT = V0 (1 - e (-T/RC))(Derivation requires calculus, and that seems a little bit out of scope for this question.)
about 500 uF
It takes 1 farad for every 1000 watts so u need 2 farads.
is a device that smoothen your half-wave rectification into a full-wave rectification after using a 4 diode and 1 resistor , after adding a capacitor , there will be a almost steady output , it charges the capacitor when is forward biased which is the first half wave , and discharge when is reverse biased to stablelize the wave into a almost same potential difference compare to a.c
1000
Medium voltage is over 1000 v, high voltage is over 45 kV.
Only electrolytic capacitors (tantalum capacitors are a type of electrolytic capacitor) are polarized.0.001 farad = 1000 microfaradThis is a value that is too large for any practical capacitor except an electrolytic, so yes it will be polarized.
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.