The velocity is gravity acceleration x time or (9.8)(1.5) = 14.7 m/s. The velocity is not dependent on the mass.
It is approx 14.7 metres per second.
Because he was 20 meters away from the blast, unless mission priority supersedes he requires 24hr rest and a medical evaluation before considering return to duty.
Although t is known as Pythagoras' theorem and thus about 2500-2600 years old, considering Pythagoras lived between 5th and 6th century BC, it was known before this. There is evidence that the Babylonians of 20th to 16th century BC (some 1000 years before Pythagoras) knew it, making it about 3600-4000 years old.
Assuming that acceleration dut to gravity is 32 ft/sec2 and that air resistance is insignificant, the answer is 2.5 seconds. To show work, at 8 ft/sec v = at = 32 t t = 1/4 second jumping up and v = 0 before free fall s = 1/2 at^2 = 16t^2 = 16x.25 x .25 = 1 foot so diver free falls 81 feet 81 = 1/2 at^2 so t = 2.25 sec 2.25 + .25 = 2.5 sec
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Linear mass density, u, can be calculated by isolating the u variable in the following equation: v = √(F/u), where v is the velocity, F is the force of tension, and u is linear mass density. Therefore, the equation would be: u = F/v2. You may need to first solve for velocity, using the equation v = fλ, where f is frequency and is λ wavelength. You may also need to solve for force of tension before solving for u. You can use the equation F = mass x gravity, where mass is in kilograms and gravity is 9.8 m/s2. After calculating these variables, you can calculate linear mass density by plugging them into this equation: u = F/v2.
because there is more air resistance
The weight exceeds the force of air resistance, but as the speed increases the air resistance increases, so the net force (weight - air resistance) falls. When the difference becomes zero the acceleration ceases and you have terminal velocity.
The horizontal velocity will be equal to the translational velocity of the ball right before it falls off the table. ============================== When we do exercises that deal with the behavior of the ball after it leaves the edge of the table, we always ignore air resistance. When we do that, the horizontal component of velocity remains constant forever, or at least until the ball hits something.
Total momentum before = total momentum afterTotal kinetic energy before = total kinetic energy afterSum of x-components of velocity before = sum of x-components of velocity after.Sum of y-components of velocity before = sum of y-components of velocity after.Sum of z-components of velocity before = sum of z-components of velocity after.
That varies, depending on the object. A massive object may take a long time to reach terminal velocity; a less massive object will reach terminal velocity faster. It basically depends on the object's mass, size, and shape.
maximum velocity is the highest possibly speed an object can travel before the forces acting on it reach an equilibrium and it is no longer able to accelerate. For example a parachutist will fall and accelerate rapidly until the air resistance pushing upwards against her downward force becomes balanced and her speed is steady, its more commonly known as 'terminal velocity' not maximum.
Before reaching terminal velocity, an object will fall faster and faster.
A falling object, if there is no significant air resistance, will fall faster and faster before it hits the ground. Similarly, a satellite in orbit around the Earth changes its direction, and therefore its velocity, all the time. (In physics, "velocity" describes a speed at a certain direction.)
This is called Terminal Velocity. Gravity pulling downwards matches the air resistance pushing upwards to cancel the acceleration out. Many people misunderstand this and believe that this means that the object falling is no longer moving, but it is speaking in terms of acceleration, not speed. So the acceleration from before terminal velocity was reached will still be in affect, but the object will be neither gaining or losing speed.
V = SQRT(2gh), where g is the acceleration of gravity and h is the height.
We will reach terminal velocity just before we hit the ground, then the result of our velocity will be terminal.
If there was no air resistance the sky diver would go on increasing in velocity until hitting the earth, under the constant force of gravity, so the velocity at impact (and hence the kinetic energy) would depend entirely on the height at which he jumped out of the plane. The formula is V2 = 2G x S, where V = velocity (meters/sec), G = 9.81 meters/sec2, S = height above Earth (meters). Then KE = 1/2 x Mass x V2, (Joules)