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A 2.7-kg box is released on a horizontal surface with an initial speed of 2.9 ms It moves on the surface with a deceleration of 0.27 ms2 Calculate the kinetic friction force on the box?
Wiki User
∙ 12y ago
Net force = 20-12 = 8N
Mass = 2 kg
Using F = ma, we get required a = F/m = 8/2 = 4 m/s2
Wiki User
∙ 12y ago
The force of kinetic friction can be calculated using the formula: force of kinetic friction = mass * acceleration. The acceleration in this case is the deceleration, so the force of kinetic friction = 2.7 kg * 0.27 m/s^2. Therefore, the kinetic friction force on the box is 0.729 N.
Wiki User
∙ 12y ago.73 N
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