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7.1g N2 (1mol N2/ 28.02g N2)(3 mol H2/ 1 mol N2)(2.0158g H2/ 1 mol H2) = 1.5 g H2

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13y ago
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8y ago

We need theoretically 22,23 moles hydrogen.

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13y ago

Six

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Q: A 7.1-g sample of N2 requires how many g of H2 for complete reaction?
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