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A bag contains 7 green and 6 red jellybeans How many ways can 5 jellybeans be withdrawn from the bag such that the number of green one withdrawn is less than 4?
JoshuaMillergp9382
The answer is four ways, thus...Withdraw 5 red - 0 greenWithdraw 4 red - 1 greenWithdraw 3 red - 2 greenWithdraw 2 red - 3 green
There are 26 ways.
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A bag contains five green marbles and four red marbles what is the odds of in favor picking a green marble on the first selection?
There is a one in 2 chance of getting a green marble.
A bag contains 3 red marbles 2 blue marbles and 5 green marbles What is the probability of selecting a red marble without replacing it in the bag and then selecting a green marble?
Total marbles in the bag = 10Number of red ones = 3Probability of pulling a red one on the first draw = 3/10 = 0.3Total marbles remaining after the first draw = 9Number of green ones = 5Probability of pulling a green one after a red one has been withdrawn = 5/9Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.
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