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A balloon payment calculator is not actually in the shape of a balloon. It is used to calculate a balloon payment; it is called a balloon payment because of its size.
a water tank in the form of an inverted cone is being emptied at the rate 6 m3/min. the altitude of the cone is 24 m, and the base radius is 12 m. find how fast the water level is lowering when the water is 10 m deep.
V = 4/3*pi*r^3dV/dt = 4/3*pi*3*r^2*dr/dt = 4*pi*r^2*dr/dt Therefore dV/dt = 5 => 4*pi*r^2*dr/dt = 5 therefore dr/dt = 5/(4*pi*r^2) Diameter = 12 metres => radius = 6 metres So dr/dt = 5/(4*pi*36) = 0.01105 metres per minute. diameter = 2*radius => rate of change of diameter = 0.2210 metres per minute.
Effusion
if vigorous enough to create heat the balloon will expand.
For a balloon that is sealed and not full the volume of air inside the balloon will increase as it is heated. This is not however how hot air balloons work. A hot air balloon is essentially a fixed volume when it is inflated. If the air inside the balloon is heated the air inside becomes less dense so some of the air exits the balloon via the mouth of the balloon. As the air inside the balloon cools it becomes more dense so some air is ingested via the mouth of the balloon to keep it full. With each heating and cooling cycle, the pressure inside the balloon remains constant, the volume of the balloon remains constant but there is this movement of air out of and back into the balloon. P=VT Poop
Xdzs
volume decreases considering the pressure is constant
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v
The hot air inside the balloon is less dense than the surrounding air, causing it to rise when heated and fall when cooled. This is because the hot air has a lower density, creating a buoyant force that lifts the balloon up or allows it to sink back down when the air cools.
assuming the balloon is closed, the air pressure would double
Heating causes the air inside the balloon to expand. Some of the warm air leaves through the bottom opening of the balloon, keeping the pressure constant.
since the balloon is moving up with a constant speed it is not accelerated or decelerated
3.5 litre if pressure is kept constant.
Heating causes the air inside the balloon to expand. Some of the warm air leaves through the bottom opening of the balloon, keeping the pressure constant.