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Is null node equal to leaf node?
No. A leaf node is a node that has no child nodes. A null node is a node pointer that points to the null address (address zero). Since a leaf node has no children, its child nodes are null nodes.
Explain in detail in a binary tree of n nodes there are n plus 1 null pointers representing children?
Induction: 1. A tree of one node has two NULL-pointers. 2. Whenever you add a node to a tree, you remove one NULL-pointer (from the parent of the new node), and add two (the child's of the new node) in the same time.
What is the algorithm to count no of nodes in singly linked list?
int numNodes = 0; Node current = root; // if root is null, the number of nodes is 0 if(current != null) { // if root is not null, we have at least one node numNodes = 1; // count all nodes while(current .next != null) { ++numNodes; current = current.next; } }
What is recursive algorithm to find the height of a binary search tree with n numbers of nodes?
Really the best way to traverse any binary tree is recursion. In this case we are going to be some node defined as having 3 values, a pointer to a left node, a pointer to a right node, and a value. then in psudocode we can do it as: int height(node n, int depth){ int leftDepth; int rightDepth; if(n.left != NULL) leftDepth = height(n.left, depth+1) else leftDepth = depth; if(n.right != NULL) rightDepth = height(n.right, depth+1) else rightDepth = depth; if(leftDepth > rightDepth) return leftDepth; return rightDepth; } Essentially what you are doing is calling the algorithm on both the left and right nodes which in turn will call it on their left and right nodes, down to where all the nodes are null. Then what is returned is the greater depth of the two; because it will traverse before returning a depth, and only traverses if there is a deeper node, it will return the depth of the deepest node, or the height of the binary tree.
How do you Count node left and Right for binary tree using PHP Codeigniter?
To count the number of left and right nodes in a binary tree using PHP Codeigniter, you would typically need to traverse the tree recursively. You can create a function that takes the root node of the binary tree as a parameter and recursively counts the left and right nodes. Within the function, you would check if the current node has a left child and recursively call the function on the left child while incrementing the left count. Similarly, you would do the same for the right child. Finally, you would return the counts of left and right nodes.
How many null branches are there in a binary tree with 20 nodes?
12
What is NULL branches in trees?
NULL branches in trees are branches that do not contain any nodes. They represent the absence of a child node in a parent node. These NULL branches are important for maintaining the structure of the tree and indicating where additional nodes can be inserted.
Is null node equal to leaf node?
No. A leaf node is a node that has no child nodes. A null node is a node pointer that points to the null address (address zero). Since a leaf node has no children, its child nodes are null nodes.
What is the Algorithm to count the number of leaf nodes in binary tree?
int countleaves(struct node* root){ if(root!=null) { countleaves(root->left); if(root->left==NULL&&root->right==NULL) { count++; } countleaves(root->right); } }
Explain in detail in a binary tree of n nodes there are n plus 1 null pointers representing children?
Induction: 1. A tree of one node has two NULL-pointers. 2. Whenever you add a node to a tree, you remove one NULL-pointer (from the parent of the new node), and add two (the child's of the new node) in the same time.
How binary tree is represented as doubly link list?
In this representation, each node contains two pointers, one pointing to its parent (null in the case of root node) and the other pointing to its child node (null in the case of leaf nodes).
What is the algorithm to count no of nodes in singly linked list?
int numNodes = 0; Node current = root; // if root is null, the number of nodes is 0 if(current != null) { // if root is not null, we have at least one node numNodes = 1; // count all nodes while(current .next != null) { ++numNodes; current = current.next; } }
What is the difference between equals 0 and equals NULL?
NULL is for pointers, 0, for numbers
In PHP a null value plus a number value is equals to what result. example null plus 6 equals?
In php mathmatical operations treat null like 0, so any number plus null equals itself. For example #!/usr/local/bin/php printf ("%d\n", null+6); printf ("%d\n", 6+null); ?> output: 6 6
What is recursive algorithm to find the height of a binary search tree with n numbers of nodes?
Really the best way to traverse any binary tree is recursion. In this case we are going to be some node defined as having 3 values, a pointer to a left node, a pointer to a right node, and a value. then in psudocode we can do it as: int height(node n, int depth){ int leftDepth; int rightDepth; if(n.left != NULL) leftDepth = height(n.left, depth+1) else leftDepth = depth; if(n.right != NULL) rightDepth = height(n.right, depth+1) else rightDepth = depth; if(leftDepth > rightDepth) return leftDepth; return rightDepth; } Essentially what you are doing is calling the algorithm on both the left and right nodes which in turn will call it on their left and right nodes, down to where all the nodes are null. Then what is returned is the greater depth of the two; because it will traverse before returning a depth, and only traverses if there is a deeper node, it will return the depth of the deepest node, or the height of the binary tree.
What is the method to determine the size of a binary tree in C?
To determine the size of a binary tree in C, you can use a recursive function that counts the number of nodes in the tree. The function should traverse the tree by recursively calling itself on the left and right subtrees, and incrementing a counter for each node visited. The base case of the recursion should be when the current node is null, indicating an empty subtree.
If your null hypothesis is Ho u1 equals u2?
yes.
