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A buffer is prepared by mixing 50.0 ml of 0.050 m sodium bicarbonate and 10.7 ml of 0.10 m naoh what is the pH for carbonic acid ka1 equals 4.5 x 10 -7 and ka2 equals 4.7 x 10 -11?
Wiki User
∙ 11y ago
0.050M x .05L = .0025 mol NaHCO3
0.10M x .0107L = .00107 mol NaOH
Excess NaHCO3 = .0025-.00107 = 0.00143
pH = pKa2 + log(.00107/.00143)
pH = 10.20
Wiki User
∙ 11y ago
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