Assuming no affects from air and a smooth geography, both bullets would fall at the same rate of 9.81 m/s^2 toward earth, and hit the ground simultaneously. You have to look at the bullet's velocity as having a horizontal and vertical velocity vectors. The vertical velocity vector is independent from that of the horizontal. The horizontal vector would be the speed at which the bullet is fired, and the vertical vector is the speed at which the bullet falls due to gravity.
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
No. That's why a bullet shot horizontally from a gun and a bullet dropped from the muzzle of the gun at the same time both hit the ground at the same time.
Both hit at the same time.
50 seconds
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
No. The horizontal distance depends on how close the the ground the gun is. From the firing position, a bullet dropped to the ground will strike the ground in the same time as a bullet shot horizontally forward.
If it was thrown horizontally or dropped, and hit the ground 3.03 seconds later, then it hit the ground moving at a speed of 29.694 meters (97.42-ft) per second. If it was tossed at any angle not horizontal, and hit the ground 3.03 seconds later, we need to know the direction it was launched, in order to calculate the speed with which it hit the ground.
No. That's why a bullet shot horizontally from a gun and a bullet dropped from the muzzle of the gun at the same time both hit the ground at the same time.
One. Only the bullet's weight. In this case, the bullet would not decelerate and will keep moving at muzzle velocity until it hits the ground.
All other factors equal (bullet mass & frontal area, angle of barrel, etc) a higher muzzle velocity will make the bullet travel further horizontally as if falls to the ground. If the barrel is level when fired , the bullet will hit the ground at the same time as a bullet dropped simutaneously from muzzle height
Both hit at the same time.
50 seconds
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
1). Your speed in the forward direction should increase somewhat, since the recoil of the shot adds to your momentum. 2). The bullet you fire in the reverse direction leaves the muzzle with full muzzle velocity and momentum in the reverse direction ... in your frame of reference. Viewed by an observer in the stationary frame of reference ... the one in which you are moving at the speed of a bullet ... the one you fire just dribbles out of the muzzle and falls straight to the ground.
Answer: 3 seconds
They will arrive at the floor together (assuming the floor is horizontal). The reason is that both the initial vertical component of the speed, and the vertical acceleration, are the same.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.