Statistics

Math and Arithmetic

Probability

789

If a coin is tossed 15 times there are 215 or 32768 possible outcomes.

There are 26 = 64 possible outcomes.

Each toss has 2 outcomes; so the number of outcomes for 3 tosses is 2*2*2 = 8

Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.

2 sides x 10 tosses, so your possibilities is 2^10 or 2x2x2x2x2x2x2x2x2x2 =1024 outcomes.

5 outcomes if the sequence is ignored. 24 = 16 outcomes in all.

9, you just have to multiply for problems like this

It depends on the definition of an outcome. If you care about the order of the tosses, <br /> you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails).

Possible outcomes of a single dice are 6 ( 1,2,3,4,5,6) So if 5 such dices are rolled then the number of possible outcomes are 6 mulitiplied by 6 five times. 6x6x6x6x6x6=46656 possible outcomes.

when you toss a coin three times, the total number of possible outcomes is

Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.

6. Possible outomes are: 1. HHH 2. HHT 3. HTH 4. THH 5. THT 6. TTT

There are 25 = 32 possible outcomes.

Two times the number of outcomes of the spin - which is not specified in the question.

There are 26 = 64 possible outcomes.

It depends on the number of sides and how many times you roll it.

When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.

2x2x2=8 possible outcomes. In general for n tosses there are 2^n outcomes.

2^2^2^2 * * * * * Actually, the conventional notation is either 2*2*2*2 or 2^4 = 16

You carry out an experiment a number of times. You make a list of all possible outcomes and record the number of times that outcome occurred.

There are 210 total possible outcomes from flipping a coin 10 times.There is one possible outcome where there are 0 heads.There are 10 possible outcomes where there is 1 head.So there are 210 - 11 possible outcomes with at least 2 heads.(1013)

The number of outcomes you would have is number of outcomes x number of times done. Or in this case, number (of outcomes on the dice) x 5 x 5 x 5 x 5 x 5 because you rolled the dice 5 times

Two possible outcomes for each flip. 2,048 possible histories of 11 flips.

It depends what you mean by outcome. If you are interested in the total number of different outcomes, then there are 6 x 6 x 6 x 6 or 1296 unique possible outcomes. If you are only interested in the total (the sum) of the resulting roll, it can be anything from 4 to 24 so there are just 21 possible outcomes.

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