You didn't give me any values, but I can give you a formula that will answer your question. The force exerted by a spring is given as F = -KX, where K is the spring constant and x is the distance the spring is compressed or stretched. When the spring is compressed fully, it has a force F. When the spring is at equilibrium(aka not stretched), it has a force of zero. We can average these to say that the Average force of a spring is F = 1/2 -KX. We can now substitute the -1/2 KX into the equation F = ma. This yeilds -1/2 KX = ma. Solve for acceleration, we get (-1/2 KX)/m = a. Multiply this quantity by the amount of time the spring pushed on the object, and you have your velocity. Hope this helps whoever asked. --An AP Physics Student Bored in Study Hall
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
2181 N/m
Hooke's law is not related to any "natural length". Rather, it defines a string constant: how much the string extends or compresses, depending on the applied force. In SI units, the spring constant would be measured in newton/meter.
The Spring is the power source for the gun. When the gun is cocked the spring compresses and when the trigger is pulled the spring releases and pushes a piston that compresses a tube fill of air that fires a BB out of the barrel.
no the spring constant is not constant on moon because there is no restoring force there
The spring constant (K) is 25 N/M, Êthe maximum velocity is Êgiven ÊbyÊ AW where ÊA is Êthe amplitude (0.32 m) and w is given by the formula (k/m)^0.5. ÊTherefore the maximum velocity is Ê2.4 m/s (0.32 x (25/0.45)^0.5).
some basic physics will tell you that the mass of the box times acceleration due to gravity times the height of the box above the ground, minus the force of the spring or the spring constant times the distance the spring stretches will equal .5 times the mass of the box times the velocity squared mgh-kx=.5mv2
Please do your homework by yourself.
No. Its potential energy does decrease.
larger the spring constant of a spring, the more stiffer it is.
2k
a system shown in figure is released from pulley from rest.pulley and spring is massless and friction is absent everywhere .the speed of 5kg when 2kg block leaves the ground is how much