1 meter per second west.
Momentum = mass * velocity. We are told that his momentum is 80kgm/s, and that his mass is 80 kg, so we can say: 80kgm/s = 80 kg × V ∴ 1m/s= V So the velocity of the man is 1 meter per second west.
Momentum = m V = (21) x (3 west) = 63 kg-m/sec west(Bold italics are vectors)
1380 kph west
Velocity = distance divided by time / Velocity = average speed over time / Acceleration = (change of) velocity divided by time elapsed Change in velocity = final velocity "minus" initial velocity divided by time elapsed
60km per hour west.
Momentum = mass * velocity. We are told that his momentum is 80kgm/s, and that his mass is 80 kg, so we can say: 80kgm/s = 80 kg × V ∴ 1m/s= V So the velocity of the man is 1 meter per second west.
20 kilograms
1
Momentum = mass x velocity. Momentum = (90 kg) x (3 m/s) Momentum = 270 kgm/s
Momentum = Mass x Velocity = 11 x 10 = 110 Ns (Newton seconds)
Momentum = mass x velocity Assuming you mean the rider is riding at 5 m/s, the momentum is 95 x 5, which is 475 kg-m/s
The asteroid's velocity component tangent to the surface of the planet at the equator is:│v│∙ sin 40oThis times the mass of the asteroid gives the impulse (F∙t) the asteroid gives tothe planet, tangent at the point of impact and in the direction of the planet rotation:m∙│v│∙ sin 40oThis time the radius of the planet gives the increment in angular momentum ofthe planet:R∙│v│∙ sin 40o
It is an example of a velocity.
Momentum = m V = (21) x (3 west) = 63 kg-m/sec west(Bold italics are vectors)
The equation for velocity is velocity=distance/time. So you would solve the problem as follows. 240km/4h=60km/h
1380 kph west
Velocity = distance divided by time / Velocity = average speed over time / Acceleration = (change of) velocity divided by time elapsed Change in velocity = final velocity "minus" initial velocity divided by time elapsed