To figure this out, use a Punnet Square.
First, set up a test cross, like this:
Rr x rr
This shows what you are crossing. Now you can make a Punnet Square.
R r
r Rr rr There is a 50/50 chance that the corn plant will have the
genotype rr.
r Rr rr
If a plant that has a round seed has a parent that has wrinkled seeds, what is its genotype?
Round seeded character is dominant over wrinkled seeds. Therefore, the genotype of wrinkled seed would be homozygous recessive i. e. rr against round seeded plants which may have either RR or Rr type of genotypes.
One-half. Doing a Punnett square, Rr x rr = 1/2 probability for heterozygous Rr, 1/2 for homozygous rr.
rr
0% of the offspring will be homozygous because one parent only has the dominant allele and the other parent only has the recessive allele so all of their offspring will be heterozygous.
RR x rr
ambot
rr, Rr
If ALL offspring are Aa, The parents are AA and aa.
The F1 generation consists of the offspring of a cross between two parents; the F2 generation consists of the offspring of a cross between two individuals in the same F1 generation.
When a red flower crosses with a white flower, it can create a pink flower. Why? Because of incomplete dominance. Incomplete dominance is when the heterozygous phenotype(offspring) is a blend of the two homozygous phenotypes(parents).
1. In the fruit fly Drosophila melanogaster, vestigial wings and hairy body are produced by two recessive genes located on different chromosomes. The normal alleles, long wings and hairless body, are dominant. Give the genotype and phenotype of F1 progeny obtained from a cross between a vestigial-winged, hairy male and a normal, homozygous female. If the F1 from this cross are permitted to mate randomly among themselves, what phenotypic ratio would be expected in the F2generation?
In a typical Mendel experiment, Mendel took two purebreeding lines (the parental generation) and crossed them to produce the 1st filial generation and sometimes would self cross these to produce the 2nd filial generation.
The probability that an offspring will have wrinkled seeds is 2 in 4 or 50%
If you cross wwgg x WwGg, each parent contributes one allele for the traits. The genotype for wrinkled (w) and green (g) seeds is wwgg, and the genotype for WwGg is heterozygous for smooth and yellow. Therefore, 0% of the offspring will be wrinkled green.
3
RrYy
Probability is the term for the chance that any specific genotype will occur in the offspring from the mating of parents. Typically the capital letter A (in this example) represents the dominant allele as opposed to the recessive allele. The probability of the possible genotypes in a monohybrid cross is 1AA:2Aa:1aa. The probability of AA is .25 or 25%.
The hybrid is the offspring so the probability is 1.
The Punnett square is a diagram that is used to predict the outcome of a particular cross or breeding experiment. It is used by biologists to determine the probability of an offspring having a particular genotype.
false
It is important to remember that the factors inherited by the first offspring of a cross have no effect at all on other offspring of that cross. For example, there is a 25% probability that offspring of a cross betweet two hybrid bean plants will inherit the factos RR. If one offspring inherits RR, there is still a 25% probability that the next offspring will also inherit RR.
Perform a test cross. Cross the organism with an organism with a homozygous recessive genotype and use the phenotypes of the offspring and a Punnett square to figure out the unknown genotype.
half white and half purple
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).