Frequency=60/6=10Hz
Time Period=1/f=1/10
It doesn't. Only the length of the pendulum and the strength of the gravitational field alter the period/frequency.
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
The period or frequency of the pendulum
Frequency = 1 / period.
Period, T , and frequency, f , are always the inverse of each other; f = 1/T
No, that's called its "period". The frequency is numerically equal to the period's reciprocal.
T=1/f .5=1/f f=2
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1/4 Hertz or 1.4 per second.
The frequency is (36/60) per second.The period is the reciprocal of the frequency = (60/36) = 1-2/3 seconds
It's not always the same. The frequency of a pendulum depends on its length, on gravity, on the pendulum's exact shape, and on the amplitude. For a small amplitude, and for a pendulum that has all of its mass concentrated in one point, the period is 2 x pi x square root of (L / g) (where L=length, g=gravity). The frequency, of course, is the reciprocal of this.
A shorter pendulum has a shorter period. A longer pendulum has a longer period.