Let x represent width. Using the formula 3x(x)=44cm, the equation is complete when x = 3.82. This means that the rectangle is 3.82 cm wide, and 11.46 cm long.
2 times (length + width)
30cm
40 meters.
The perimeter of a rectangle is the distance around the rectangle. The area of a rectangle is the space inside the rectangle. To calculate either one you need the length and the width of the rectangle. To calculate the area multiply the length times the width. To calculate the perimeter add the length+width+length+width (that is the distance all the way around)
The distance around it, two times the sum of the length and width.
18.4cm by 22.4cm
8X36
The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).
That would be 3 x 9 inches.
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
twice length + twice width = perimeter In this example, L= 3W 2(3W)+2(W)=64 8W=64 W=6 L =3W L=18 The dimensions of this rectangle are: 18 by 6
2 times (length + width)
30cm
The rectangle is 9 inches wide X 27 inches long. Clue: width is X; length is 3 times width (3X). Perimeter is width plus length times two (X + 3X times 2 = 8X). 8X = 72; X = 9. 3X = 27. Proof: 9 + 9 (2sides) +27 + 27 (2 lengths) = 72.
length times width
It is not. The perimeter of a 1 cm square is 4 cm. The perimeter of a 5 km * 15 km rectangle is 4000000 cm: a million times as large!
4w + 4w + w + w = 8w+2w= 10w=150 w=15 l=60