64 centimetres.
To find the diagonal of a rectangular floor slab, you can use the Pythagorean theorem. First, convert the dimensions from millimeters to meters: 12300 mm is 12.3 m and 33700 mm is 33.7 m. Then, apply the formula (d = \sqrt{(length^2 + width^2)}): [d = \sqrt{(12.3^2 + 33.7^2)} \approx \sqrt{(151.29 + 1135.69)} \approx \sqrt{1286.98} \approx 35.9 \text{ m}.] Thus, the diagonal of the slab is approximately 35.9 meters.
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides
The term for the line that divides them is a diagonal.
In a parallelogram of forces, the resultant force is represented by the diagonal of the parallelogram drawn from the initial point of the forces to the opposite corner. The magnitude and direction of the resultant force are determined by the length and orientation of this diagonal in the parallelogram.
The term you are looking for is "oblique." Muscles that are described as oblique run at an angle or diagonal to the midline of the body.
The length of one side of a square with a 16-centimeter diagonal is: 11.31 cm
15 cm for the diagonal.
rectangle
It is formed by the diagonal of a rectangle
~7.1 cm
Using Pythagoras' theorem the length of the diagonal is 15 units
The principal diagonal of the room also requires its height.
It is a rectangle.
Do you just type questions from your homework into this website? If so, frack off.
considering you gave no additional information, it is impossible to know
Select any vertex.There are three faces that meet at that vertex. Find the vertex at which the other three faces meet. The line joining these two vertices is the principal diagonal of the rectangular prism.
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.