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For this problem, we are looking at two variables: pressure and temperature. Therefore, we will use Gay-Lussac's law or

P1 ÷ T1 = P2 ÷ P2

P1 = 3.00 ATM

T1 = 2.00oC = 275 K*

P2 = P

T2 = 10.0oC = 283 K*

*Note that all temperatures must be in Kelvin

3.00/275 = P/283

P2 = 3.09 ATM

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Q: The pressure inside a hydrogen-filled container was 2.10 at 21 What would the pressure be if the container was heated to 94C?
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