d=1/2at^2
80=1/2(9.80)t^2
80=4.90t^2
t^2=80/4.90
t=square root 16.33
t=4.04s
v=d/t
v=1330/4.04
v=330 m/s
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
There are several definitions. not just one. Average velocity in a direction = Average displacement (distance) in that direction/time Instantaneous velocity in a direction = derivative of displacement in that direction with respect to time Average velocity in a direction = Initial velocity in that direction + Average acceleration in that direction * time Instantaneous velocity in a direction = Definite integral of acceleration in that direction with respect to time, with initial velocity at t = 0 Then there are others in which time is eliminated.
Positive acceleration.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
AccelerationWhen the velocity of an object increases or decreases, that means it has accelerated. Acceleration is defined as the rate of change of velocity.If an object's final velocity is greater than its initial velocity, that indicates positive acceleration. If an object's final velocity is less than its initial velocity -- if, say, it slows down and comes to a stop -- then that indicates negative acceleration. Deceleration is another way of saying negative acceleration. But . . .It is good idea to avoid using the term deceleration, because an object that is experiencing negative acceleration may slow down, come to a stop momentarily, and then reverse direction and speed up -- IN THE OPPOSITE DIRECTION!You can think of it this way: When an object is slowing down, its acceleration is in the direction opposite to its motion. We think of that as negative acceleration.
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
There are several definitions. not just one. Average velocity in a direction = Average displacement (distance) in that direction/time Instantaneous velocity in a direction = derivative of displacement in that direction with respect to time Average velocity in a direction = Initial velocity in that direction + Average acceleration in that direction * time Instantaneous velocity in a direction = Definite integral of acceleration in that direction with respect to time, with initial velocity at t = 0 Then there are others in which time is eliminated.
firstly, we should know what is meaning of accelerate i.e(to increase)that means acceleration is something which increases some physical quantity.In mechanics,acceleration means rate of change of velocity per unit time .a=v-u/twhere v=final velocity, u=initial velocity ,t=time& a=accelerationnow ,if the change in velocity is positive then i.e final velocity is greater than initial velocity.Suppose to be positive acceleration or simply acceleration.But when change in velocity is negative then acceleration is negative suppose to bedeceleration.Important thing is that acceleration is vector .so ,positive or negative accelerationindicates direction of acceleration.hence , force ,by Newton's second law.acceleration tends to increase the velocity of a moving body in the direction of motion while deceleration tends to decrease the velocity of the moving body applies in opposite direction of motion upto zero velocity after which it accelerate means increase velocity of the body but in opposite direction of initial direction of motion.
If a shell is fired from the ground with velocity of 1600 m and an angle of 64 to the horizontal then it would have a horizontal rang of 55.0. This is considered math.
its upward at some specified angle
inital velocity (u) should be less
Positive acceleration.
To take the magnitude of the velocity you will need to square both the horizontal and vertical components and then take the square root of their sum. So: V=(Vx2+Vy2)1/2
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.