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water can't actually reach that temperature because temperature is actually a measurement of how fast the particles in an object are moving. once they reach boiling point (100) the water particles cant go any faster and so they evaporate and change into a gas. if you left the water on the heat then it would eventually all evaporate and there would be nothing left in the container. if you put a lid on the container it would explode because the particle's would have no where to escape.
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∙ 12y ago
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∙ 16y agowhen water freezes= 0oC and 32oF also at 459 R
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∙ 15y ago272 kelvin is -1.15 degrees Celsius, where water freezes.
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∙ 8y agoThat's about 0 degrees Celsius. At that temperature, ice melts (or water freezes). That is equivalent to zero degrees Celsius (Centigrade). Water freezes at that temperature.
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∙ 9y agofreezes
freezes.
===============
Also melts.
melts
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∙ 9y agoWater freezes at 273 degrees Kelvin. This is based on a scale where zero degrees Kelvin is known as absolute zero.
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∙ 14y ago273 Kelvin is approx 0°C. Therefore water freezes.
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∙ 6y agoPure water will boil at normal pressure.
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What does water do at a temperature of 273 K?
Is way past boiling point. The Kelvin units of measurement for temperature works with Celsius in such a way: K= C-273 That conversion is not exact (the number is not exactly 273) however it gets the point across. ================================================= This contributor begs to differ. 273.15 K is the temperature at which water freezes. K = C + 273.15 At 273.15 K, C = 0 and you have fresh ice.freezesfreezes.
What were the initial and final temperature of water in kelvin scale?
I think you might have wanted to tell us a little more information. It may be of use to know that absolute zero, 0 K = -273 C; the freezing point of water 0 C =273 K, and the boiling point of water, 100 C = 373 K
What temperature does water boil at in Kelvin?
It boils at 373 degrees kelvin. Kelvin is just Celsius plus 273. Water boils at 100C, 100+273=373, so 373K.
The temperature at which the vapor pressure of a liquid has an external pressure of 1 atm is?
0 degrees Celsius, 273 degrees Kelvin, 32 degrees Fahrenheit.
What is 0 C on the Kelvin scale?
0 ºC = 273 K
What happens to water when is reaches the temp of 273 k?
The water melts
What is the formula of celsius to kelvin?
K= C + 273 Example- the freezing point of water is 0 c 0 + 273= 273. So water freezes at 273 k
How do you convert 0 degrees Celsius to kelvin scale?
Conversion formula: [K] = [°C] + 273.15 = 0 + 273.15 = 273.15 K
What is the melting point of water on the kelvin scale?
273 K
In science what is a formula of a kelvin and celsius?
To convert Kelvin to Celsius - the given temp in K minus 273 To convert Celsius to Kelvin - the given temp in C plus 273 I hope this is the one u r expecting and it helps u !!
Temperature of 273 k is temperature at which what does what?
Triple point of water, where water freezes/melts
What are the temperatures for freezing water on the Kelvin temperature scale?
273 k
Which shows the formula for converting from kelvins to degrees Celsius C (95 K) plus 32 C 59 (K 32) C K 273 C K plus 273?
C = K -273
What does water do at a temperature of 273 K?
Is way past boiling point. The Kelvin units of measurement for temperature works with Celsius in such a way: K= C-273 That conversion is not exact (the number is not exactly 273) however it gets the point across. ================================================= This contributor begs to differ. 273.15 K is the temperature at which water freezes. K = C + 273.15 At 273.15 K, C = 0 and you have fresh ice.freezesfreezes.
The freezing point of pure water at sea levels is 0 c what is that in kelvins?
The equivalent is 273 K.
Give a relationship between Celsius scale on Kelvin scale?
To get from Celsius to Kelvin, +273 And obviously, -273 to get from Kelvin to Celsius E.g. -273oC = 0K (Absolute zero) 0oC = 273K (Freezing temp. of water) 25oC = 298K (Standard temp.)
What is the volume of the gas at 200 degrees c if it is 25 L at 0 degrees c?
Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
