Assume
Length of the train =x metre,speed be y metre/ sec
Time taken to cross the pole x/y sec
Time taken to cross the platform=length of train+length of platform/ speed of train
x/y=15 x=15y
x+100/y=25
15y+100=25y
10y=100
Y=10 metre/ sec
x=15y = 100
heyy someone help me..to solve this problem
After the nose of the train reaches the platform, it takes some number of seconds for thenose to reach the far end. At that time, the whole train is lined up with the whole platform.Then after that, it takes the same number of seconds again for the caboose to reach the far end,and the train to completely clear the platform.So the total time that there's some overlap between the train and platform is twice the timethe train takes to move the length of the platform, which is also the length of the train.Distance = (speed) x (time)180 meters = (speed) x (9 seconds)speed = (180/9) = 20 meters per second
245m
20 m/s
its simple 72km/hr=72000m and 1hr=3600s........so train travelling per sec=72000/3600=20m........thus train travelling in 7s=140m which is answer :)
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is
Jacob Torino.
200m. Here's the work:The speed of the train in meters per second is:(36km/hr)(1000m/km) / (3600s/hr) = 10 m/sIf it takes 80 seconds to cross, then the distance traveled in 80s at 10m/s is:(10m/s)(80s) = 800mNow, imagine this:The front end of the train travels 800 meters from the time it reaches the bridge until the back end is clear of the bridge. This means that the length of the train equals the distance traveled minus the length of the bridge.So:800m - 600m = 200mThe train is 200m long.
To totally cross the bridge the train must travel (850m + 150m) 1 km. 1 km in 100 seconds is 10 m/s roughly 20 mph, so the answer is yes, with ease.
Km/hr to m/s = 5/18 Speed60 km/hr Cross pole in 9sec Length=speed*time Speed =60*5/18=50/3m/s 50/3*9=150 Length of the train =150
The platform on the north side (forgot the number)
The common nouns in the sentence are: people, platform, train.
120 km/h = 120,000m/hr = 33.333 m/s Distance travelled in 50 seconds = 33.333 * 50 = 1666.666 metres Tunnel length = distance travelled - train length - 1666.666 - 135 = 1531.666metres