2n2 / n = 2n
The problem cannot be solved because there is no equation (or inequality) in the question: only three disjoint terms.
n squared minus six.
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
am * an = am+n
2n2 / n = 2n
The problem cannot be solved because there is no equation (or inequality) in the question: only three disjoint terms.
n squared minus six.
Adding a capacitor in parallel with our load(inductive) this would make our voltage and currents in phase n hence a maximum power factor.
it is the same as adding a negative number to a positive number
2*2*n2
less loud it takes the power and splits in half
If you put your second router next to the first one, the answer is no. You can put the second router in another part of building and create so called bridge which allows to increase coverage.
The power of a quotient is the quotient of the power! (a/b)^n = (a^n) / (b^n) where a/b is the quotient and n is the power.
10 N
2a to the second power. If you combine the like terms, (a to the second power + a to the second power), it would be the same as 2a to the second power.
to find the answer, you have to find the prime factorization of the two monomials 4mn^3 2*2*m*n*n*n ---------- = ------------------ 10n^2 2*5*n*n then you cross out the common numbers (so in this case: 2, n, and n) the the ones that are left are your fraction in simplest form ANSWER: 2mn ------ 5