Let's work that out together.
X + 10 = 34 so 34 - 10 = X so 34 - 10 = 24
Elga is X so is 24.
57
A = E - 9 A + E = 87 that is, (E - 9) + E = 87 2E - 9 = 87 2E = 87 + 9 = 96 E = 96/2 = 48
11 and 12
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
26
If Alvin is 7 years younger than Elga, then Alvin + 7 = Elga. If the sum of their ages is 87, then Alvin + Elga = 87. Substitute Alvin + 7 in the previous equation to get Alvin + (Alvin + 7) = 87. Reduce that and get 2 Alvin = 80 which means that Alvin = 40. That means that Elga = 47.
It is 50 years.
a = 3e a + e = 76 ∴ 3e + e = 76 e = 76/4 e = 19 ∴ a = 3 × 19 a = 57 Alvin is 57 years old, and Elga is 19
57
Alvin +Elga = 56 3 : 1 56 รท 4 = 14 Alvin = 56 - 14 = 42 Elga = 14
Elga is 24, because this would mean that Alvin's age is 48, and 24+48=72.
A = E - 9 A + E = 87 that is, (E - 9) + E = 87 2E - 9 = 87 2E = 87 + 9 = 96 E = 96/2 = 48
Alvin is 44 and Benjamin is 11.
28
JFK had three brothers. Joseph was 2 years older, Robert was 8 years younger and Edward (Ted) was 15 years younger. By the time JFK was president, Joseph was already deceased.
11 and 12
There ages are now 5 and 9 respectively because and in 3 years time 2/3 of 12 = 8