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An arrow is shot straight up at an initial velocity of 250 ms How long will it take the arrow to hit the ground?
Wiki User
∙ 9y ago
51 seconds.
Wiki User
∙ 14y ago
Wiki User
∙ 9y ago51 seconds
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An arrow is shot straight up at an initial velocity of 200 meters per seconds. How long will it be before beginning to fall?
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
Why an arrow shot horizontally and an arrow dropped straight down from the same height will hit the ground at the same time?
yes because they have the same gravitational potential
You shoot an arrow into the air. Two seconds later the arrow has gone straight upward to a height of 33.0 m above its launch point. What is the arrow's initial velocity?
The acceleration of gravity is [9.8 meters per second2] directed downward.After two seconds of vertical flight, the upward speed of the arrow is (9.8 x 2) = 19.6 m/sless than its initial velocity.Average speed = 1/2 (Vi + Vf) = 1/2 (Vi + Vi-19.6) = Vi - 9.8Distance = (average speed) x (time) = 33(Vi - 9.8) x (2) = 33Vi - 9.8 = 16.5Vi = 16.5 + 9.8 = 26.3 m/s
Velocity is represented graphically by an what?
By an arrow, a vector. Velocity is a vector quantity that must have both magnitude (speed) and direction (bearing).
What are two velocity components of projectile motion?
The magnitude of its Velocity (Speed), and its Direction. These are the components of the Arrow (Vector) that represents its MOTION.
An arrow is shot straight up at an initial velocity of 250ms How long will it take to hit the ground?
This is a velocity question so u need to use uvaxt
An arrow in flight has an initial velocity of 65 meters per second and 10 seconds later it has a velocity of 35 meters per second Which is the acceleration of the arrow?
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
An arrow is shot straight up at an initial velocity of 200 meters per seconds. How long will it be before beginning to fall?
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
When an archer shoots an arrow straight up with an initial velocity magnitude of 100.0 ms. After 5.00 s the velocity is 51.0 ms. At what rate is the arrow decelerated?
The change in velocity is 51-100 = -49 m/s This occurred over a period of 5 seconds so The (negative) acceleration - aka - deceleration is (-49 m/s)/(5 s) = -9.8 m/s²
What happens when you shoot an arrow straight in the air?
An arrow shot vertically into the air will lose velocity and reverse direction. When it begins to descend, the fletching will quickly cause it to re-orient with the point downward. It will accelerate until it reaches its terminal velocity. Assuming an atmospheric density of 1.3 kg/m^3, and an arrow with a drag coefficient of 1.2, a weight of 0.23 N (200 grains), cross-sectional area of 23.48 mm^2, I calculate a terminal velocity of 112.6 m/s. That's about the same as the initial velocity when shot from a compound bow! One question remains, however: does the arrow have enough time during its descent to reach terminal velocity? That would depend on how high you shot it in the first place. Roughly speaking, though, the faster it was going when it left the bow, the faster it will be going when it reaches the ground.
What is represented by the length of the arrow in a vector arrow?
Velocity.
Why an arrow shot horizontally and an arrow dropped straight down from the same height will hit the ground at the same time?
yes because they have the same gravitational potential
When was Straight as an Arrow created?
Straight as an Arrow was created on 2008-11-30.
Range of a bow and arrow?
When a bow is pulled back with the arrow in place, elastic potential energy is stored in the bow and thus arrow. When released, all that potential energy is converted into kinetic energy. EPE=KE. Since you know the "pounds" of the bow, the weight of the arrow, and how high the arrow is from the ground you can calculate the an arrows range assuming it is parallel to the ground. Derivation: KE= .5 X Mass X Velocity^2 Distance= Velocity X Time Time the Arrow is in Flight= [( vertical distance x 2)/ (32 ft/sec^s)]^(1/2)
Does a heavy arrow or a light arrow have more kinetic energy when shot from a compound bow?
A heavy arrow will have more kinetic energy when shot from a compound bow compared to a light arrow. Kinetic energy is determined by both the mass and velocity of an object. Although a heavy arrow may have a lower initial velocity, its greater mass compensates and results in higher kinetic energy than a lighter arrow.
How do you solve this An arrow is fired into the air with an initial velocity of 160 feet per second. The height in feet of the arrow t seconds after it was shot into the air is given by the function?
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.
You shoot an arrow into the air. Two seconds later the arrow has gone straight upward to a height of 33.0 m above its launch point. What is the arrow's initial velocity?
The acceleration of gravity is [9.8 meters per second2] directed downward.After two seconds of vertical flight, the upward speed of the arrow is (9.8 x 2) = 19.6 m/sless than its initial velocity.Average speed = 1/2 (Vi + Vf) = 1/2 (Vi + Vi-19.6) = Vi - 9.8Distance = (average speed) x (time) = 33(Vi - 9.8) x (2) = 33Vi - 9.8 = 16.5Vi = 16.5 + 9.8 = 26.3 m/s
