To convert kilograms to grams, you multiply the mass in kilograms by 1,000, since there are 1,000 grams in a kilogram. Therefore, 0.25 kg of the substance is equal to 0.25 × 1,000 grams, which is 250 grams. Thus, the required mass of the substance is 250 grams.
Scientific notation is required for very large or very small numbers.
If required: 4.67221*105
5.2*101 (although the exponent, 1, is not required).
Any profession that is required to work with very large or very small numbers.
The Word notation for 150,000 is One Hundred Fifty Thousand. The Scientific Notation for 150,000 depending on required significant figures is 1.50 x 105.The Roman Numeral Notation for 150,000 is CCCIƆƆƆƆƆƆ.
Scientific notation is required for very large or very small numbers.
If required: 4.67221*105
depends on the experiment - more information required
5.2*101 (although the exponent, 1, is not required).
the scientific process is required for this substance.
Any profession that is required to work with very large or very small numbers.
It is impossible to tell how long from the start of the experiment it was before all of the substance turned into a liquid without more information about the experiment. Perform the experiment again and use a timer to determine the length of time required to turn the substance into a liquid through heating.
The Word notation for 150,000 is One Hundred Fifty Thousand. The Scientific Notation for 150,000 depending on required significant figures is 1.50 x 105.The Roman Numeral Notation for 150,000 is CCCIƆƆƆƆƆƆ.
To convert 0.25 kilograms to grams, you multiply by 1,000 (since there are 1,000 grams in a kilogram). Therefore, 0.25 kg is equal to 250 grams. Thus, you need 250 grams of the substance for the experiment.
The dissolving medium in the experiment is typically water or a specific solvent chosen based on the solubility of the substance being dissolved. The choice of dissolving medium depends on the nature of the substance and the conditions required for the experiment.
9.4*102 or 9.40*102 if required to show 3-digit precision.
Scientific notation is in the form d.nnn... x 10^p where d is a single non-zero digit and nnn are any digits, to the required number as required and p is the power of 10 required to multiply the d.nnn...by to get the original number (p can be thought of as (and calculated by) the number of digits that the decimal point needs to more to get back where it was in the original number, a negative number to the left, a positive number to the right). 8.76 x 10^9 and 6.52 x 10^-3 are already in scientific notation. 13.27 x 10^5 = 1.327 x 10^6 in scientific notation.