if hypotenuse is 4 then each side is 4 divided by sqrt 2 = 2.828 with two angles 45 degrees
The triangle height is 2 so area is 1/2 base x height =1/2 times 4 times 2 = 4
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
Area of the right isosceles triangle: 0.5*16*16 = 128 square units
The length of the hypotenuse, alone, is not sufficient to determine the area of a triangle.
do you want to know the area in a isosceles triangle or what?
Yes providing that it's an equilateral triangle or a right angle isosceles triangle.
Area of any triangle is: 0.5*base*perpendicular height
Area of isosceles triangle: 0.5*5*7 = 17.5 square cm
Yes. The two equal sides would measure 3.
Yes providing that it is an equilateral triangle or a a right angle isosceles triangle other wise it's not possible
Using Pythagoras' theorem the other leg works out as 60 meters. 1/2*25*60 = 750 square meters
An isosceles right triangle is a 90 degree triangle that the two non-hypotenuse sides are equal. http://mathworld.wolfram.com/IsoscelesRightTriangle.html Area of a triangle is 1/2 x b x h Area of an isosceles right triangle is 1/2 b2 144 cm2 = 1/2 b2 2 (144 cm2) = 2(1/2 b2) 288 cm2 =b2 16.97 cm = b So the base and height each equal 16.97 cm The hypotenuse can be solved by the Pythagorean Theorem a2 + b2 = c2 288 + 288 = c2 576 = c2 (576).5 = (c2).5 24 = c So the sides of an isosceles right triangle with the area of 144 cm2 are 16.97 cm, 16.97 cm, and 24 cm.
V= area of the triangle x length