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Assume that a solution forms the product Mercury (I) acetate. The product formed is _______.

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Q: Assume that a solution forms the product mercury liquid acetate The product formed is?
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How do you make 50mM ammonium acetate solution?

One mole of ammonium acetate is equal to 77.08g (this is the formula weight, FW, of ammonium acetate, which can be found on the side of the bottle). Another way of representing this is 77.08/mol (so, in one mole of ammonium acetate, there are 77.08grams of ammonium acetate).We have to use the FW value to calculate molarity (moles of solute per L of solvent).I am not sure what volume of the 50mM solution is desired, so I will assume that you need 1 L.50mM is equal to 50milli-moles of solute/1 L of solvent, which is the same as 0.05moles/L. This is what the math looks like:77.08g/mol ammonium acetate x 0.05mol/L = 3.854g/LSo, to make a 50mM solution of ammonium acetate in 1L of water, you will need to dissolve 3.854g of ammonium acetate into 1L of water.


Tris buffer as pH by HCl why not for sodium acetate?

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