At what speed does a 1.00 kg mass have a kinetic energy of 1.00 joules?

Answer 1

***Answer 1***

Remember, KE= (1/2)m(v^2),

1 eV=1.6*10^-19 J

-you need to convert, since 1J= 1N*m

m of an electron is 9.1*10^-31 kg

m of a proton is 1.67*10^-27 kg

Good luck!

***Answer 2***

Answer 1 only works for non-relativistic speeds, also when you are dealing with Nuclear Physics you DO NOT want to convert out of eV.

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E(total) = Energy Kinetic +Energy rest

But in Nuclear Physics E(total) is actually;

E^2 = (pc)^2 + (mc^2)^2

E(total) = E(kinetic) + E(rest)

=> 1.00keV = (pc)^2

from there you should be able to finish it.

Answer 2

Units of Joule = m*v^2/s^2 KE=0.5*m*v^2 KE = 1 J m = 1 kg 1=0.5*1*v^2 2= v^2 v=1.4 m/s

Answer 3

810*1.6*10^-19=0.5*mv^2

v=16.97*10^6