Because 1/3 are blue and 1/2 are red and the rest are green we can calculate that 1/6 of the marbles are green.
1/3 = 2/6
1/2 = 3/6
2/6 + 3/6 = 5/6 which leaves 1/6 green.
Since there are 7 green marbles we know there must be 7 x 6 total.
The answer is 42 marbles.
10 Green marbles, 13 Blue marbles.
Let X = the number of green marbles. X+3 = the number of blue marbles. X + (X+3) = 23 2X + 3 = 23 2X = 20 X = 10 or the number of green marbles.
a+b=23 b=a+3 a+b a+(a+3)=23 a+a=23-3 2a=20 a=10 green marbles=10 blue marbles =23-10 =13
There are at least 11 green marbles in the bag.
hypergeom. f(1;13,3,1) * f(1;12,5,1)
10 Green marbles, 13 Blue marbles.
He will have 13 blue marbles and 10 green marbles.
He has 10 green marbles.
Let X = the number of green marbles. X+3 = the number of blue marbles. X + (X+3) = 23 2X + 3 = 23 2X = 20 X = 10 or the number of green marbles.
a+b=23 b=a+3 a+b a+(a+3)=23 a+a=23-3 2a=20 a=10 green marbles=10 blue marbles =23-10 =13
The ratios are: red : green = 2 : 3 = (2×3) : (3×3) = 6 : 9 green : blue = 9 : 4 → ratio of red : green : blue = 6 : 9 : 4 There are 6 + 9 + 4 = 19 parts 76 marbles ÷ 19 parts = 4 marbles per part → red: 6 parts = 6 × 4 marbles per part = 24 red marbles → green: 9 parts = 9 × 4 marbles per part = 36 green marbles → blue: 4 parts = 4 × 4 marbles per part = 16 blue marbles To check: red + green + blue = 24 marbles + 36 marbles + 16 marbles = 76 marbles in the bag.
There are at least 11 green marbles in the bag.
it is 6/9 simplifyyou get 2/3.
8:6
The fraction is 3/15.
0No blue marbles in the bag.
Red, blue, green or yellow.Red, blue, green or yellow.Red, blue, green or yellow.Red, blue, green or yellow.