Br2 Cl2 -- 2BrCl How many moles of BrCl form when 2.74 mol Cl2 react with excess Br2?

Answer 1

While Im not particularly sure that reaction even happens, I guess one could figure it out none the less.

If you have 2.74 mol of Cl2 you would expect to get 5.48 mol of BrCl. Because each Cl2 can make 2 BrCl so double the number of moles. Br has a molecular weight of 79.90 and Cl of 35.45 so together that's 115.35 Grams/mol. Since you have 5.48 mol all you have to do is multiply the two numbers together and cancel out the "mol" units to get 631.12 grams of BrCl... again which makes this reaction seem completely unrealistic.... what good is that much BrCl.

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Well, silly you need to balance it first and provide the equation~

So you probably have: Br2+Cl2=2BrCl correct?

So you have 2.74mol Cl2, you need to find ___molBrCl

2.74molCl2 X (2molBrCl/1molCl2) = 5.48molBrCl

Answer 2

So you have 2.74mol Cl2, you need to find ___molBrCl

2.74molCl2 X (2molBrCl/1molCl2) = 5.48molBrCl

Hope this helps! :]