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Calculate the mass of carbon dioxide present in 445 mL at 225 degrees celsius and 1.783 ATM?
Wiki User
∙ 14y ago
the equation you need is PV=nRT
P=1.783 atm
V=445 mL (convert to L by multiplying by .001)
n=moles(what you're looking for)
R=.08206
T=225 (change Celsius to Kelvin by adding 273)
solve for n to get the amount of moles and then multiply the moles by the molar mass of CO2 to get the mass :)
Wiki User
∙ 14y ago
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