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Answered 2016-03-23 16:02:20

It is not possible because the average velocity is equal to the displacement in a given time interval, ie:

V = (displacement) / (time interval)

As the zero displacement average speed will also be zero.

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Answered 2016-03-08 11:26:45

No. A non-zero average velocity means, precisely, that there is a displacement.

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No, you cannot have a zero displacement and a nonzero average velocity. If the object has not moved any where how can you attain a nonzero velocity? You cannot.


Average velocity is zero if the displacement is zero. Average velocity = Displacement/Time = 0/Time = 0.


An object moving in a circular path at constant speed will have a non-zero average speed and zero average velocity since velocity is a vector parameter,


When the velocity is zero at the crossing of the time axis, the displacement must be a full maximum or minimum. Scroll down to related links and look at "Displacement - Velocity- Acceleration".


If the car has an average speed of 65 mph, when it returns to its starting point, it will have a displacement of zero and an average velocity of zero, because velocity has both speed and direction.


i will give u an illustration, consider an object projected (thrown)with some initial vertical velocity from the ground such that it traces a open downward parabolicpath, in that path the vertical displacement of the body from the point of projection to the point where it strikes the ground is equal to zero,but it have some velocity.


the displacement is zero.Note that distance travelled would not be zero though. as velocity doesn't signify anything abt distance travelled.speed will give you what distance you travelled.Since average velocity is zero, some component is negetive some positive or no movement at all. whichever case may be, the displacement will be zero.



Yes, you can. Example: An object going around in a circle.


The average velocity is pretty close to zero. Velocity is a vector, so its average value is the total displacement divided by the total time. Since the racquet probably starts and finishes in the player's bag in the player's home, the average velocity is zero.



Yes. An object moving at constant velocity would have zero acceleration.


Speed is distance by time and velocity is displacement by time. If an object is moving with speed distance can never be zero but displacement can. So we say velocity can be zero.


Yes, if, for example, a car races around a circuit, its total displacement is zero and so its velocity, at the end of every lap, is zero.


If the average velocity of a duck is zero in a given time interval, it can be said that the displacement of the duck is also zero. The duck did not leave its original position.


Definitely. Acceleration is defined as a change in velocity, so as long as the velocity doesn't change, acceleration is zero.


No it does not. If the velocity is 10 m/s for 10 secs and 0 for another 10 secs, then the average is 5 m/s which is non-zero over the 20 second period. But the instantaneous velocity is zero for the period from 10 to 20 seconds.


Every time the unicycle returns to its starting point, the average velocity equals zero. The total displacement divided by the time.


As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.


For the purposes of this explanation, velocity will be given in m/s. If it's starting position is the same as its stopping position, the radio controlled car will have an average velocity of zero meters per second. This is because average velocity is displacement/time interval. Displacement is change in position and is a vector quantity, which has magnitude and direction. Average velocity is the displacement/time interval, and is also a vector quantity, including the magnitude of the speed and its direction. If you start and stop walking at the same position, your displacement is 0m, even if you walked a distance of 100 miles, and your average velocity would be 0m/s. Refer to the related link below for an illustration.


A simple example is a ball tossed into the air. When the ball reaches its apex -- its highest point -- its instantaneous velocity is zero. If we assume that up is the positive direction, the ball's velocity is positive when it is initially tossed into the air, but it slows immediately. That is, its velocity becomes less positive until it reaches zero velocity. After that point, the velocity becomes increasingly negative (because down is the negative direction). Until the ball returns to earth and reaches the height at which it was initially thrown, its average velocity is non-zero. If the ball is allowed to hit the ground, its average velocity will be slightly negative, which is still non-zero. But it still had an instant -- at its apex -- when its velocity was zero.


Every time the unicycle returns to its starting point, the average velocity equals zero. C. The total displacement divided by the time.


Zero. That's the instant at which its velocity changes direction. In order to do that, its magnitude has to be zero at that point in time.


Zero average velocity does not equal zero dislacement. Zero average velocity equals zero average displacement. :) Wouldn't it be the other way around? Let's say I take my mouse from its center position (from which we'll define the displacement) and move it quickly to the right some arbitrary distance and then equally quickly back to the center. Then, I move it slowly the same distance to the left and equally slowly back to center again. Over this entire time, since the motions are symmetric (that is, the mouse spends the same amount of time moving in the positive direction as the negative), the average velocity must be zero. Also, we're back to the central position, so the net displacement must be zero. However, since we spent more time moving the mouse on the left, the time-averaged displacement must point to the left. Would you agree? Answer given by Neetu Singh Lambha.


Yes, if it returns to its starting place, the average velocity for the cycle will be zero. The average SPEED, however, will not be zero.



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