Every line has an equation that can be written in the general form Ax + By + C = 0, where A, B, and C are real numbers, and A and B are not both 0.
First, we'll find the slope of the line:
m = (y2 - y1)/(x2 - x1) = (9 - 4)/(9 - 3) = 5/6. Now,
(y - y1) = m(x - x1) Point-slope form;
(y - 4) = (5/6)(x - 3)
y - 4 = (5/6)x - 15/6 Subtract (5/6)x and add 15/6 to both sides;
y - 3/2 - (5/6)x = 0 arrange terms;
-(5/6)x + y - 3/2 = 0 Multiply by -1 both sides;
(5/6)x - y + 3/2 = 0
Suppose the equation of the line is y = mx + c where m and c need to be determined. The slope of the line = (difference in y-coordinates of the two given points)/(difference in x-coordinates of the two given points) = (-6 - 2)/(0 - 4) = -8/-4 = 2 So m = 2 ie the equation of the line becomes: y = 2x + c where c still needs to be determined. The point (0, -6) is on the line. That is, when x = 0, y = -6. Substituting in the equation, -6 = 2*0 + c so that c = -6 and the equation of the line is y = 2x - 6
A lateral is the correct answer (if your doing the crossword puzzle I find to be very popular)
Equation: y-6 = 2/5(x-10)Solution: 5y = 2x+10
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They are all the points where the graph crosses (or touches) the x-axis.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
Suppose the equation of the line is y = mx + c where m and c need to be determined. The slope of the line = (difference in y-coordinates of the two given points)/(difference in x-coordinates of the two given points) = (-6 - 2)/(0 - 4) = -8/-4 = 2 So m = 2 ie the equation of the line becomes: y = 2x + c where c still needs to be determined. The point (0, -6) is on the line. That is, when x = 0, y = -6. Substituting in the equation, -6 = 2*0 + c so that c = -6 and the equation of the line is y = 2x - 6
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
If you have two equations give AND one parametric equation why do you need to find yet another equation?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
You solve an equation containing y.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x