No, this cannot be answered. This is explained below:
Please remember that
Without molar mass (in g/mol) molarity cannot be calculated from just knowing it is an triglyceride with density 0.91 g/mL (which is of no significance for this question, many trig's have a comparable density).
Molarity = Grams/(Molecular Weight X Volume)
Molarity = Grams/(Molecular Weight X Volume)
molarity x molecular weight x volume=gram molarity= gram/molecular weight x volume abdulrazzaq
Yes, you definitely need to know the molecular weight of a compound to calculate molarity.
molarity is the number of moles dissolved per volume of a solution in dm cube molarity=mass of solute in gram __________________ 1 * _________________ molecular mass of solute volume of solution in dm cube OR molarity=no.of moles ________________ volume of solution in dm cube
The molecular mass of sodium chloride is 58,44 g; 13 g is equal to 0,222 moles.
You know the molarity and you know the volume. First off you find the moles. Molarity divided by 1000, multiplied by the volume in cm^3. Then you multiply the moles by the molecular mass of the solute, to get the weight in grams.
grams divided by the molecular weight to get to moles moles divided by volume to get molarity
No. The reason is that low molecular weight compounds tend to have high molarity. As an example NaF is 42.5 molecular weight. So 42.5g dissolved in 1 liter of water would only be 4.25% but be 1 molar. Proteins tend to have every high molecular weight. So if a protein was say 1000 molecular weight, a 10% solution would contain 100g but only be 0.1 molar.
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
You know the chemical formula. You can get the molecular weight from this. You need the end volume and you also need the mass of solute.
Molarity = moles of solute/Liters of solution Find moles glucose, which is molecular formula------C6H12O6 154 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.8548 moles C6H12O6 Molarity = 0.8548 moles C6H12O6/1 Liter = 0.855 M glucose ---------------------------