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What is the remainder when 2 to the power 33 is divided by 17?
To find the remainder of ( 2^{33} ) when divided by 17, we can use Fermat's Little Theorem, which states that if ( p ) is a prime and ( a ) is an integer not divisible by ( p ), then ( a^{p-1} \equiv 1 \mod p ). Here, ( p = 17 ) and ( a = 2 ), so ( 2^{16} \equiv 1 \mod 17 ). Thus, ( 2^{33} = 2^{32} \cdot 2 \equiv (2^{16})^2 \cdot 2 \equiv 1^2 \cdot 2 \equiv 2 \mod 17 ). Therefore, the remainder is 2.
What type of antifreeze should you use for a 1999 Nissan XE Pickup?
Preston in yellow jug or equiv. mixed 50/50 with distilled water
When a number is divided by 4 the remainder is 2. When the same number is divided by 5 the remainder is 1. What is that number?
Let the number be ( x ). According to the problem, we have two conditions: ( x \equiv 2 \mod 4 ) and ( x \equiv 1 \mod 5 ). The first condition implies that ( x ) can be expressed as ( x = 4k + 2 ) for some integer ( k ). Substituting this into the second condition gives ( 4k + 2 \equiv 1 \mod 5 ), which simplifies to ( 4k \equiv -1 \equiv 4 \mod 5 ), leading to ( k \equiv 1 \mod 5 ). Thus, ( k = 5m + 1 ), and substituting back gives ( x = 4(5m + 1) + 2 = 20m + 6 ). The smallest positive solution occurs when ( m = 0 ), giving ( x = 6 ).
The least number which when divided by 35 leaves remainder of 25 when divided with 45 leaves a remainder of 35 and when divided by 55 leaves 45 as remainder is?
To find the least number that meets these conditions, we can express the problem in terms of congruences. We have: ( x \equiv 25 \mod 35 ) ( x \equiv 35 \mod 45 ) ( x \equiv 45 \mod 55 ) These congruences can be rewritten as: ( x \equiv -10 \mod 35 ) ( x \equiv -10 \mod 45 ) ( x \equiv -10 \mod 55 ) Since all three congruences have the same form, we can solve for ( x ) using the least common multiple of the moduli (35, 45, and 55), which is 1035. Adding 10 to account for the negative remainder, we find that ( x = 1035 - 10 = 1025 ). Thus, the least number is 1025.
What is 1lb gold equiv in oz?
12 oz, it measures on the troy scale.
What food did children in factories eat 1800?
they probably would not eat but if they had the chance they would eat stale bread! if Jude equiv we Jeffery gifts fug use Huff
What is the gas to oil mixture ratio on a Husqvarna 325R X-series weedeater?
Lubricant typeHusqvarna or equiv. at 50:1 Right off the web site I use husky oil
Why can you not get a remainder of 2 when dividing a square number by 3?
A square number can only yield specific remainders when divided by 3. When a number ( n ) is divided by 3, it can have a remainder of 0, 1, or 2. The possible square results are ( 0^2 \equiv 0 ), ( 1^2 \equiv 1 ), and ( 2^2 \equiv 1 ) (mod 3). Thus, the only possible remainders when dividing a square number by 3 are 0 or 1, never 2.
What are the names of the eight races swum in the olympic?
d equiv. o2wef 'Acrux [4i3ru i4rt . that is what i think!
Type of oil on mercury Milan?
The 2010 Milan requires 5W20 Synthetic Blend (Motorcraft preferred or equiv.)
When a perfect square is divided by 3 the remainders are or?
When a perfect square is divided by 3, the possible remainders are 0 or 1. This is because any integer can be expressed in one of three forms modulo 3: 0, 1, or 2. Squaring these forms gives the results: (0^2 \equiv 0 \mod 3), (1^2 \equiv 1 \mod 3), and (2^2 \equiv 1 \mod 3). Thus, perfect squares can only yield remainders of 0 or 1 when divided by 3.
What are the different parts of a cow?
FlankRumpChuckLoinBrisketRibsNeckRoundTwistBackShoulderHockDewclawPasternNavelDewlapKneeHeadMuzzleEarsPollCrestCrop (equiv. to horse's withers)TailheadShank/Cannon boneFetlock JointUdder (cow) or Scrotum (bull)
