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No, when you lie down in the hot sun with your hands facing up they don't get tanned but the rest of your arm does. Haven't you noticed that dark skinned people have pale palms, if your palms tanned then dark skinned people would also have dark palms wouldn't they? So, no i don't think you can unless you use fake tan!
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∙ 14y ago
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How old do you have to be to work at palm beach tan?
18
What do royal palm turkey eggs look like?
Tan with dark freckles.
Where is alaina miceli?
Palm Beach Gardens, Florida. Working on a schmecksy tan, I'm sure.
Rhyming word pairs for calm man?
Mellow fellow.
Why is the palm of your hand white?
cos it's consist of a skin layer called stratum lucidum..
What can you get with 1 dollar?
many things, a soda, chocolate candy, and so on.. or perhaps a tiny plastic palm tree, a cheek covered in spray tan, or a coat hanger, apparently.
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
What is a antonym of pale?
Tan Tan
What is tan20tan32 plus tan32tan38 plus tan38tan20?
This may not be the most efficient method but ... Let the three angle be A, B and C. Then note that A + B + C = 20+32+38 = 90 so that C = 90-A+B. Therefore, sin(C) = sin[(90-(A+B) = cos(A+B) and cos(C) = cos[(90-(A+B) = sin(A+B). So that tan(C) = sin(C)/cos(C) = cos(A+B) / sin(A+B) = cot(A+B) Now, tan(A+B) = [tan(A)+tan(B)] / [1- tan(A)*tan(B)] so cot(A+B) = [1- tan(A)*tan(B)] / [tan(A)+tan(B)] The given expressin is tan(A)*tan(B) + tan(B)*tan(C) + tan(C)*tan(A) = tan(A)*tan(B) + [tan(B) + tan(A)]*cot(A+B) substituting for cot(A+B) gives = tan(A)*tan(B) + [tan(B) + tan(A)]*[1- tan(A)*tan(B)]/[tan(A)+tan(B)] cancelling [tan(B) + tan(A)] and [tan(A) + tan(B)], which are equal, in the second expression. = tan(A)*tan(B) + [1- tan(A)*tan(B)] = 1
Y is the California flag important?
The Flag in California is important in many ways.First of all it represents the state of California and symbolizesthe unique things that California has and other states arent fourtunate to have, like the palm trees .California has a lot of palm trees and is well know for its heat.People in California are most likely to be tan.
Where can I get a gift card for tanning in San Diego?
You can get a tanning gift card from a salon called Palm Bay Mega Tan for San Deigo, CA and you will be able to purchase it online by visiting their companies site.
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
