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The maximum tensile stress will occur at the fixed end on the side the load is applied to. An equal compressive stress will occur on the opposite side. Shear stress is typically neglected because it is relatively small compared to the stresses due to the bending moment. Stress S is found using:

S = M*c/I

where M is the moment at the point in question (maximum at the fixed end), I is the moment of inertia of the beam/tube, and c is the distance from the centroid/centerline to the point in question. Again the maximum stress occurs farthest from the load and farthest from the centerline/centroid (I don't recall which one is used, but they're the same if the beam/tube is symmetrical).

Moment is simple,

M = P * L

where P is the load perpendicular to the beam in units of force, and L is the length from the load to the point in question or fixed end.

c is also simple, for a 1"x1" box tube c equal 1" divided by 2. So c = 0.5".

The moment of inertia I will depend on the shape of the tube or beam and can be easily calculated using the appropriate formula from a table.

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14y ago
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13y ago

simple: applied load times the lengh of that section. If Fixed end is right of free end and load is applied up, FEM = (-). If load is applied down, FEM = (+)

Direct Displacement method for solving beam with cantilever end

http://www.public.iastate.edu/~fanous/ce332/displ/2spancant.html

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12y ago

failure will always occur at the fixed end.

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Q: In a cantilever beam point load is applied on free end where failure will occur?
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When a cantilever is loaded with udl the maximum bending moment occurs at?

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