The sum 9 + 99 + 999 + 9999 + 99 999 + ....
where the last number to be added consists of nine digits of 9 becomes:
(10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ...
where the last multiple of 10 has nine zeros.
There are nine pairs of brackets altogether.
Add the multiples of 10 first and then subtract 9:
The digit 1 appears 9 times in the final answer.
Using exactly eight 9's : 999 + ( 99/9 ) - ( 9/ .9 ) [ 999 + 11 - 10 = 1000 ] or (999 + 9/9) x ( 99-9) [ (999 +1 ) x 1 ] --(obviously the five 9's are enough : 999 + 9/9 )
There is a choice of 8 digits for the first digit and a choice of 10 digits for each of the remaining 6, so there are 8 x 106 = 8,000,000 (eight million) 7-digit numbers which do not start with 0 or 4.
Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.
The digit 8 represents eight thousands.
Eight hundred thousand.
the eight all the way to the right
There are not 99999999 eight digit numbers - unless you allow numbers with leading 0s.
Eight (8) of them do.They are1221243642486384 .
Eight of them.
Definitely earlier than the year 2000. In April 2000, Portsmouth moved from six-digit local numbers to eight-digit numbers, as well as changing to the new, short area code of 023. (For example, Portsmouth City Council's number changed from 822251 to 92822251.) Instructions at the time referred only to how to convert six-digit local numbers to eight-digit numbers, so it is reasonable to assume that no five-digit numbers remained at that time.
No. The largest value you can get from adding eight 1-digit numbers is 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 = 8*9 = 72
52,355,500 is an eight-digit number.
eight
1047, 1407, 4017, 4071 are four (out of eight) such numbers.
you say one number first then the other one for example 789 you say seven eight and then nine
Assuming whole numbers and a leading zero does not count: 10,234,567
There are 76 such numbers. Eight more if you allow numbers to start with 0.
There is a choice of 8 digits for the first digit and a choice of 10 digits for each of the remaining 6, so there are 8 x 106 = 8,000,000 (eight million) 7-digit numbers which do not start with 0 or 4.